Question

What is the mole fraction of the solute in a 1.00 m aqueous solution?

Answer 1

Molality = Moles of solute / Mass of solvent in kg

Molality is given as 1
Therefore,
1 mole of solute is dissolved in 1 kg of water

Moles of solvent = 1000 g / (18 g/mol)
= 55.55 mol

Mole fraction of solute = 1 / (1 + 55.5)
= 0.017

Mole fraction of solute is 0.017

Answer 2

Hey !!

1.0 m aqueous solution means 1 mole of the solute is present in 1000 g of water.

1000 g of H₂O = 1000 / 18 moles = 55.5 moles

 nH₂O = 55.5

Mole fraction,

xsolute = nsolute / n solute + nH₂O = 1 / 1 + 55.5

            = 0.0177

Hope it helps you !!