Question

what is the mole fraction of the solute in a 1.00m aqueous solution?

Answer 1

Molality = Moles of solute / Mass of solvent in kg

Molality is given as 1
Therefore,
1 mole of solute is dissolved in 1 kg of water

Moles of solvent = 1000 g / (18 g/mol)
= 55.55 mol

Mole fraction of solute = 1 / (1 + 55.5)
= 0.017

Mole fraction of solute is 0.017

Answer 2

Answer:

Explanation:

1.00 molal aqueous solution means that 1 mol of solute is dissolved in 1 Kg. of water.

Number of moles of solute = 1

Number of moles of water(solvent) = 1000/18= 55.556

mole fraction of solute = no. of moles of solute/(no. of moles of solute +no. of moles of solvent)

mole fraction = 1/(1+55.5)

= 1/56.5

=0.01769 = 0.0177

so answer is 0.0177