Question

What is the mole % of n2 in the mixture if the density of a non reacting gaseous mixture (ch4 and n2) is 0.75 g/litre.

Answer 1

Explanation:

Density =VolumeWeight

At S.T.P., 1.3=22.4Weight⇒Weight=22.4×1.3=29.12g

Weightmixture=29.12=WeightO2+WeightN2=nO2MO2+nN2MN2=x×32+(1−x)×28

x=0.28 mole

(where n represents the molecular weight and x represents mole fraction)

Moles of O2=0.28

At S.T.P., pressure =1 atm

Partial pressure of O2=ntotalnO2×pressure=10.28×1=0.28 atm.