What is the molecular formula of compound of boron with hydrogen if mass of 1L of this compound is equal to the mass og 1L of N2 and the boron content in the compound is 78.2% ?
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See my sis, the compound must be B2H8 which is an arachonoborane compound, symbolized as BnHn+6
First you must calculate with them as taking BXHY,
THEN Find equation, I write you these equations, one is x/y =4
And x+y =28 which is the molecular weight of n2, solving these you must get the molecular formula.
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