Question

what is the molecular mass of a substance which contains 9 atoms of carbon 13 atoms of hydrogen 2.33 g of other component​

Answer 1

Answer:

Mass of 9 atoms of carbon = 9x12 amu = 108 u

Mass of 13 atoms of hydrogen = 13x1 amu =13 u Mass of 2.33 X${{10}^{-23}}$ g of other component

= (1 u)X(2.33 X${{10}^{-23}}$ g)/(1.66 x${{10}^{-24}}$g)

= 14.04 u

Molecular mass of the substance

= (108+ 13 +14.04 )u = 135.04 u

Answer 2

The Correct Question is as follows:

What is the molecular mass of a substance each molecule of which contains 9 atoms of carbon, 13 atoms of hydrogen and 2.33 x 10^-23 g other component?

NCERT Some Basic Concepts Of Chemistry

Calculating the mass of 9 atoms of Carbon

= 9 x 12 amu

= 108 u

Calculating the mass of 13 atoms of Hydrogen

= 13 x 1 amu

= 13 u

Calculating mass of 2.33 x 10^-23 of other component

= Mass of Other Substance / Avogadro's constant

Substituting the values known to us in the formula above we get:

= (1 u) x (2.33 x 10^-23 g) / (1.66 x 10^-24 g)

= 14.04 u

Now,

Calculating the molecular mass of the substance

By Adding all the masses:

= 108 u + 13 u + 14.04 u

= 135.04 u

Therefore, the molecular mass of the substance is 135.04 u.