what is the molecular mass of substance each molecule of which contain 4 atom of carbon and 10 atom of Hydrogen
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Are you sure you copied the question correctly?
"2.33 x 10^-3 g" per molecule describes a crazy-huge molecule, where a single molecule could be weighed on a sensitive scale.
As it stands, your problem works out to:
(2.33 × 10^-3 g/molecule) × (6.023 × 10^23 molecules/mol) = 1.40 × 10^21 g / mol.
The 9 atoms of C and 13 atoms of H are vanishingly small (at least 20 orders of magnitude) compared to 10^21 g/mol, so they can be neglecte
"2.33 x 10^-3 g" per molecule describes a crazy-huge molecule, where a single molecule could be weighed on a sensitive scale.
As it stands, your problem works out to:
(2.33 × 10^-3 g/molecule) × (6.023 × 10^23 molecules/mol) = 1.40 × 10^21 g / mol.
The 9 atoms of C and 13 atoms of H are vanishingly small (at least 20 orders of magnitude) compared to 10^21 g/mol, so they can be neglecte
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Answered by
1
Are you sure you copied the question correctly?
"2.33 x 10^-3 g" per molecule describes a crazy-huge molecule, where a single molecule could be weighed on a sensitive scale.
As it stands, your problem works out to:
(2.33 × 10^-3 g/molecule) × (6.023 × 10^23 molecules/mol) = 1.40 × 10^21 g / mol.
The 9 atoms of C and 13 atoms of H are vanishingly small (at least 20 orders of magnitude) compared to 10^21 g/mol, so they can be neglecte
"2.33 x 10^-3 g" per molecule describes a crazy-huge molecule, where a single molecule could be weighed on a sensitive scale.
As it stands, your problem works out to:
(2.33 × 10^-3 g/molecule) × (6.023 × 10^23 molecules/mol) = 1.40 × 10^21 g / mol.
The 9 atoms of C and 13 atoms of H are vanishingly small (at least 20 orders of magnitude) compared to 10^21 g/mol, so they can be neglecte
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