Question

What is the molecularity of reaction for ‘CH3COOC2H5+H2O-CH3COOH+C2H5OH’?
please explain the whole method.......

Answer 1

Answer:

Number of molecules of the reactant(s) whose concentration changes during the chemical change is called order of reaction. For example, the reaction Page 9 For any doubt contact on whatsApp 9045693981 Page 9 Page 9 CH3COOC2H5 + H2O → CH3COOH + C2H5OH is a bimolecular reaction but its order is 'one'.

Explanation:

It is a pseudo first order reaction. The true rate law is

Rate = k [CH3COOC2H5] [H2O]

But the solvent water is present in such a large excess that it's concentration remains constant. Hence [H2O]= constant = k'

Therefore the rate law becomes

Rate = k [CH3COOC2H5] k' = k” [CH3COOC2H5]

since k” = k k'

Thus the reactions shows first order rate law. Hence it's a pseudo first order reaction.

Answer 2

Answer:

The given reaction is a pseudo first order reaction. This is because since H2O is taken in excess, its concentration does not affect the rate, as it remains almost constant. However, the molecularity of this reaction is 2 as 2 molecules of the reactants react to form the product.

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