Question

What is the moment of inertia about its centre of gravity of a 7.5 kg thigh if the thigh s length is 35 cm and its radius of gyration is 50% of its length?​

Answer 1

${\pmb{\frak{\underline\red{Given:-}}}}$

• Centre of gravity = 7.5 kg

• Thick length = 35 cm.

• Radius of gyration = 50%

${\pmb{\frak{\underline\red{Solution:-}}}}$

$\rm\longmapsto{Radius \: of \: gyration \: = \: \frac{1}{2} \times \: 35 \times \: {10}^{ - 2} }$

Using formula:-

$\longmapsto\rm \boxed{ \rm{I = mk ^{2} }}$

So,

$\longmapsto\rm{I =7.5 \times (35 \times \frac{1}{2} ) ^{2} }$

$\longmapsto\rm{75 \times 0.1225 \times \frac{1}{4} }$

$\longmapsto\rm \boxed { \rm{0.23 \: {kg \: m}^{2} }}$

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@Shivam

#BeBrainly