Question

What is the moment of inertia of a ring about a tangent in the plane of the circle of the ring

Answer 1

your answer is in this pic

Answer 2

Dear Student,

◆ Answer -

I(tangent) = 3MR²/2

● Explanation -

We know that, moment of inertia of a ring about its diameter is MR²/2.

Applying law of parallel forces, the moment of inertia of a ring about a tangent in the plane of the circle of the ring is -

I(tangent) = I(diameter) + MR²

I(tangent) = MR²/2 + MR²

I(tangent) = 3MR²/2

Hence, the moment of inertia of a ring about a tangent in the plane of the circle of the ring is 3MR²/2.

Thanks dear...