Question

What is the moment of inertia of a ring about its diameter?​

Answer 1

Answer:

depends on axis u take

Explanation:

suppose a ring is kept on a surface. Now, if axis is perpendicular to surface on which the ring is kept then MI = MR² and if axis is along the surface or parallel to surface then it is MR²/2.

Hope this helps...

Answer 2

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➡The moment of inertia of a hoop or thin hollow cylinder of negligible thickness about its central axis is a straightforward extension of the moment of inertia of a point mass since all of the mass is at the same distance R from the central axis.

➡By the law of perpendicular axes the sum of moments of inertia of a ring about two mutually perpendicular diameters is mr^2. So the diameters being symmetric moment of inertia about each Axis is 1/2mr^2. ... So moment about a tangent is 3/2mr^2.

I hope it's help uh