what is the moment of inertia of a uniform circular disc of radius R and mass M about an Axis passing through its centre and normal to the disc? the moment of inertia of the disc about any of its diameter is given to be (1/4)MR^2.
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The answer of u r question is.......✌️✌️
✖️What is the Momentum of inertia of a uniform circular disc of radius and mass ✖️
Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️
M.I of the disc about any diameter
ID = 1/4 MR^2
⭕️⭕️By the Theron of perpendicular axis⭕️⭕️
M.I of the disc about any axis through the center or normal to disc= M.I of the disc about any diameter + M.I about perpendicular diameter.
I = ID + ID = 2 × 1/4 MR^2
=1/2 MR^2
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Hope it helps to uu buddy!!☺️☺️☺️☺️☺️☺️
Thank you....⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️
__________________________________
__________________________________
The answer of u r question is.......✌️✌️
✖️What is the Momentum of inertia of a uniform circular disc of radius and mass ✖️
Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️
M.I of the disc about any diameter
ID = 1/4 MR^2
⭕️⭕️By the Theron of perpendicular axis⭕️⭕️
M.I of the disc about any axis through the center or normal to disc= M.I of the disc about any diameter + M.I about perpendicular diameter.
I = ID + ID = 2 × 1/4 MR^2
=1/2 MR^2
_________________________________
_________________________________
Hope it helps to uu buddy!!☺️☺️☺️☺️☺️☺️
Thank you....⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️⭐️
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