Physics, asked by dezzire, 1 year ago

what is the moment of inertia of a uniform circular disc of radius R and mass M about an Axis passing through its centre and normal to the disc? the moment of inertia of the disc about any of its diameter is given to be (1/4)MR^2.


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Answered by TheEmpress
59
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Answered by Anonymous
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The answer of u r question is.......✌️✌️

✖️What is the Momentum of inertia of a uniform circular disc of radius and mass ✖️


Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️✍️


M.I of the disc about any diameter


ID = 1/4 MR^2


⭕️⭕️By the Theron of perpendicular axis⭕️⭕️

M.I of the disc about any axis through the center or normal to disc= M.I of the disc about any diameter + M.I about perpendicular diameter.


I = ID + ID = 2 × 1/4 MR^2

=1/2 MR^2


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