Question

What is the moment of Inertia of Ring passes through the axis drom centre of
mass.
​

Answer 1

Answer:

Moment of Inertia of ring about an axis perpendicular to its plane is I=MR

2

By perpendicular axis theorem , moment of Inertia about any diameter I

′

=

2

I

=

2

MR

2

Moment of Inertia about any tangent is

I

1

=I

′

+MR

2

=

2

MR

2

+MR

2

=

2

3MR

2

=

2

3I