Question

what is the moment of inertia of solid cylinder perpendicular and passing through end​

Answer 1

Answer:

Instead of dealing with the entire cylinder at once, a simpler technique would be to divide it into infinitesimally thin discs.

Explanation:

• The moment of inertia of the disc along the central axis is then extrapolated to the transverse axis using the perpendicular axis and parallel axis theorems.
• Once you get the resulting moment of inertia for the disc along the transverse axis, integrate it across the whole length of the cylinder to get the cylinder's moment of inertia along its transverse axis.
• The moment of inertia of a disc along its central axis is given by Idisk=12mR2, where m is the mass of the disc and R is the radius of the disk's circular portion.
• The moment of inertia of a body is calculated using the Parallel axis theorem: I=Ic+Mh2, where Ic is the moment of inertia of the body about its centre, M is the body's mass, and h is the distance between the two axes.
• Moment of inertia of a body using the Perpendicular axis theorem: I=I1+I2, where I1 and I2 are the moments of inertia of the body in the plane to which the I we must obtain is perpendicular.