What is the momentum of a 0.165 kg hockey puck moving at 20.0 m/s?
Answers
Answered by
0
Answer:
0.034 m/s
Explanation:
The event is an inelastic collision event.
Here is what we know from the question:
the mass of the puck is
m = 0.105
k
g
m=0.105 kg with initial velocity
u = 24 m / s
u=24 m/s.
the mass of the goalie is
M
=
75
k
g
M=75 kg with initial velocity
U
=
0
m
/
s
U=0 m/s.
Let the velocity of the goalie and puck immediately after catching the puck be
v
v.
By applying conservation of linear momentum, we have:
Momentum Before Collision
=
Momentum After Collision
M
U
+
m
u
=
(
M
+
m
)
v
make
v
the subject
v
=
M
U
+
m
u
M
+
m
=
0
+
0.105
k
g( 24 m / s ) 75 k g + 0.105
k g ≈ 0.0335 m / s
The goalie slides with a speed of 0.034 m/s after catching the puck.
Similar questions