Question

What is the momentum of a 39.2 N bowling ball with a velocity of 7.00 s?

Answer 1

F=ma

m= F/A= F/G = 39.2N/9.8 m/s^2 = 4.00 kg

p= mv = 4kg * 7.00 m/s = 28.0 kg*m/s

The momentum is 28.0 kg*m/s

Answer 2

The momentum of the ball is 28 kg-m/s.

Explanation:

Given that,

Weight of the bowling ball, W = 39.2 N

Velocity o the ball, v = 7 m/s

We need to find the momentum of the ball. We know that the momentum of a ball is given by the product of mass and its velocity. It is given by the formula as :

$p=mv$

m is the mass of the ball

Weight,

$W=mg\\\\m=\dfrac{W}{g}\\\\m=\dfrac{39.2}{9.8}\\\\m=4\ kg$

Momentum,

$p=4\ kg\times 7\ m/s\\\\p=28\ kg-m/s$

So, the momentum of the ball is 28 kg-m/s. Hence, this is the required solution.

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Momentum

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