Question

What is the momentum of a 6.0 kg bowling ball with a velocity of 2m/s²?(Ans:12kgm/s)
Can anyone tell the steps?

Answer 1

Answer:

$= 12m \div {s}$

Step-by-step explanation:

$p = m {v}$

$p = 6 \times 2 \times 2$

$p = 12m \div s$