What is the momentum of a 6.5 kg bowling ball with a velocity of 3.0 m/s?
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Answer:
momentum p = 19.5 kgm/s
Explanation:
momentum( p) = mass(m) × velocity (v)
p=?
m=6.5kg
v=3m/s
p=mv
p=6.5×3
p=39/2=19.5
unit kgm/s
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