Question

What is the momentum of a photon with a de Broglie wavelength of 4.6 m? Estimate h as 6.63 × 10-34J s and keep 3 significant figures. a)1.05 × 10-34 kg∙m/s b)3.24 × 10-34 kg∙m/s c)1.44 × 10-35 kg∙m/s d)1.44 × 10-34 kg∙m/s

Answer 1

Answer:

6.7

Explanation:

Answer 2

Answer:

The photon's momentum up to three significant figures is $1.44\times 10^{-34}kg-m/s$.

Explanation:

Given,

The de-Broglie wavelength of a photon, λ = $4.6m$

The Planck's constant, h = $6.63\times 10^{-34}J-s$

The photon's momentum, p =?

As we know,

• The momentum of a photon is calculated by the equation given below:
• p = $\frac{h}{\lambda}$
• p = $\frac{6.63\times 10^{-34} }{4.6}$
• p = $1.441\times 10^{-34}kg-m/s$

The photon's momentum up to three significant figures is $1.44\times 10^{-34}kg-m/s$.