What is the most simplified expression for 4 c squared d + 3 d c minus 2 (d c squared + c d) + 6 c squared d squared
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Answer:
The simplified expression is
cd[1 + 2c ( 1 + 3d )].
Given:
- The given expression is
- 4c²d + 3dc - 2(dc²+cd) + 6c²d²
Solution:
=> 4c²d + 3dc - 2(dc² + cd) + 6c²d²
=> 4c²d + 3dc - 2(dc²+cd) + 6c²d²
=> 4c²d + 3dc -2dc² - 2cd + 6c²d²
=> 2c²d + dc + 6c²d²
=> cd(2c + 1 + 6cd)
=> cd[1 + 2c ( 1 + 3d )]
The simplified expression is
cd[1 + 2c ( 1 + 3d )].
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