Question

What is the multiplicative inverse of (1/2)^4÷(1/3)^4+(-1/2)3?​

Answer 1

the multiplicative inverse is 16/79

Answer 2

$(\frac{1}{2})^{4} \div ( \frac{1}{3})^{4} + ( - \frac{1}{2})^{3}$

$( \frac{1}{2} \times 3)^{4} + ( - \frac{1}{8})$

$( \frac{3}{2})^{4} + ( - \frac{1}{8})$

$\frac{81}{16} - \frac{1}{8}$

$\frac{81 - 2}{16} = \frac{79}{16}$

multiplicative inverse :- $\frac{16}{79}$