Question

What is the multiplicative inverse of - (a+b/a-b) ​

Answer 1

Answer:

In mathematics, a multiplicative inverse or reciprocal for a number x, denoted by 1/x or x−1, is a number which when multiplied by x yields the multiplicative identity, 1. The multiplicative inverse of a fraction a/b is b/a. For the multiplicative inverse of a real number, divide 1 by the number.

Answer 2

Concept:

The multiplicative inverse of any integer is a different number that produces 1 when multiplied by the original number.

Given:

$- (a+b/a-b)$

To find:

multiplicative inverse of ​$- (a+b/a-b)$

Solution:

The number when divided by itself, gives 1, i.e.,

$- (a+b/a-b) * \frac{1}{ - (a+b/a-b)} = 1$

It can be observed that the value $\frac{1}{ - (a+b/a-b)}$ when multiplied with original number gives 1.

therefore,  

multiplicative inverse of ​$- (a+b/a-b)$ is $\frac{1}{ - (a+b/a-b)}$

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