Question

What is the multiplicative inverse of
$2 \frac{3}{11} \times \frac{1}{3}$
​

Answer 1

Answer:

hope my answer helps you..

Answer 2

$\huge\sf\blue{Question:} \:$

What is multiplicative inverse of :

$2 \frac{3}{11} \times \frac{1}{3}$

$\huge\sf\blue{Solution:} \:$

What is multiplicative inverse?

★ Multiplicative inverse is the reciprocal of the number for example: b/a = a/b. a/b is the multiplicative inverse.

In this question first we will solve the question then do it's inverse.

$\displaystyle{ \implies \: 2 \frac{3}{11} \times \frac{1}{3} }$

• Converting mixed fraction to improper fraction.
• 11 X 2 + 3
• 22 + 3
• 25

$\displaystyle{ \implies \: \frac{25}{11} \times \frac{1}{3} } \:$

$\displaystyle{ \implies \: \frac{25}{33} } \:$

• 25/33 is the result

❖ Now we will do it's multiplicative inverse.

$\displaystyle{ \implies \: \: \frac{25}{33} = \frac{33}{25} } \:$

∴ The multiplicative inverse is 33/25.

$\huge\sf\blue{More \: to \: Know :} \:$

$\bf{\dag}\:\:\underline{\textsf{Fraction Rules :}}\\\\\bigstar\:\:\sf\dfrac{A}{C} + \dfrac{B}{C} = \dfrac{A+B}{C} \\\\\bigstar\:\:\sf{\dfrac{A}{C} - \dfrac{B}{C} = \dfrac{A-B}{C}}\\\\\bigstar\:\:\sf\dfrac{A}{B} \times \dfrac{C}{D} = \dfrac{AC}{BD}\\\\\bigstar\:\:\sf\dfrac{A}{B} + \dfrac{C}{D} = \dfrac{AD}{BD} + \dfrac{BC}{BD} = \dfrac{AD+BC}{BD} \\\\\bigstar\:\:\sf\dfrac{A}{B} - \dfrac{C}{D} = \dfrac{AD}{BD} - \dfrac{BC}{BD} = \dfrac{AD-BC}{BD}\\\\\bigstar \:\:\sf \dfrac{A}{B} \div \dfrac{C}{D} = \dfrac{A}{B} \times \dfrac{D}{C} = \dfrac{AD}{BC}$