Science, asked by faizmaqsoodhisua, 1 year ago

what is the n factor for disporportionation rxn

Answers

Answered by priya201709otqosa
1
n factor for such rxn is n1*n2/n1+n2  ( \frac{n1*n2}{n1+n2} )
Answered by piyush9163
0
n factor for disporportionation rxn==n1+n2/n1n2
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