Question

what is the n factor of ch3cooh​

Answer 1

Hello friends...

• I would assume you are oxidizing acetic acid to CO2 and H2O since those are its thermodynamically more stable products. The reaction would be as follows:

• CH3CO2H + 2 O2 ---> 2 CO2 + 2 H2O
• 3- 3+ 0 4+ 2-
• The n-factor is defined as number of moles of electrons lost or gained per mole of the reactant.

• In the case of carbon, the methyl group has a formal charge of 3- at carbon and the formal charge the carbonyl carbon is 3+, whereas the formal charge of the carbon in CO2 is 4+. However, the actual charges on each carbon are not completely relevant so you can simply take the average of the electrons lost (7 + 1)/2 = 4. Therefore, your n-factor is 4.

hope it's helpful for you...

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