Question

what is the n factor of feso4 in acidic medium​

Answer 1

Answer:

You can solve this easily by using the equivalents concept

number of euivalents = number ofmoles x n factor

no. of moles of feso4  x n factor of feso4 = number of moles of kmno4 x n factor of kmno4 .

n factor of feso4 =1 [fe 2+--------> fe 3+]

n factor of kmno4 in acidic medium = 5 [ kmno4----------> Mn 2+]

so  by putting the values  we get

2 x 1 = no. of moles of kmno4 x 5

no. of moles of kmno4 = 2/5 =0.4

Answer 2

Answer:

n factor =1

Explanation:

FeSO4 becomes Fe^+3 in acidic med

so

x-2=0

x=2

OS Change = 3-2=1

ON Change = 1*1= 1

therefore N factor = 1