Question

what is the n factor of nabr salt?​

Answer 1

$<font color= " red">$ 2(BrO3)- becomes Br2. Here +10 charge on bromine changes to 0. But n factor is calculated only for one ion and here there are two (2(BrO3)-) ions. Therefore n factor of sodium bromate in this reaction is 10/2 = 5.

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