what is the n of HCL when 3 ml of 10n is diluted to 500ml
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500 ml of 2 N HCl :
Molarity =2 M
No of moles =2×0.5=1 mole
500ml of 5N HCl :
Molarity =5 M
No of moles =5×0.5=2.5 moles
Total moles =3.5 moles
Total volume =500+500=1000 ml=1 L
Normality =
1
3.5
=3.5N
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