what is the natural root if m2+6m+9=0
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Answer:
m = (-3), (-3)
Explanation:
m2+6m+9=0
m2+(3+3)m+9=0
m2+3m+3m+9=0
m(m+3) +3(m+3) = 0
(m+3)(m+3)=0
From above equation,
m+3=0
m= -3
m+3=0
m=-3
Thank you
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