Question

What is the nature and the equation formed by the graph
Pls help me out
I will mark you as the brainliest

Answer 1

Answer:

Given:

A graph has been provided in diagram. It's a graph between Time period ( T) and Gravitational acceleration (g)

To find:

Nature of equation formed by this graph

Concept:

We can see that the line in the graph is passing straight and through origin (0,0). So we can say that the graph is having positive slope and zero intercept :

Taking a standard linear equation :

$\: \: \: \: \boxed{ \blue{ \huge{ \bold{y = mx + c}}}}$

We can say that m (slope) is positive and c (intercept ) is zero.

So the equation can be derived as follows :

$T \: \propto \: \dfrac{1}{ \sqrt{g} }$

Introducing a constant k , we get :

$T \: = \: \dfrac{k}{ \sqrt{g} }$

So final Equation is :

$\boxed{ \red{ \huge{ \bold{T \: = \: \dfrac{k}{ \sqrt{g} } }}}}$

Answer 2

$\huge\mathfrak\green{Answer:-}$

Given:-

We have been given a graph between Time period(T) and gravitational acceleration(g).

To Find:-

The nature and equisition of the equation formed by graph.

Solution:-

The straight line in the graph has coordinates(0,0). Therefore it has positive slope and zero intercept.

We know that,

Y = mx + c

where m is the slope which in this case is positive and c is intercept which in this case is zero.

Therefore,

$T ∝ \frac{1}{ \sqrt{g} }$

We need to introduce a constant say R.

=> We get,

$T = \frac{R}{ \sqrt{g} }$

Therefore, The final equation is :

$T = \frac{R}{ \sqrt{g} }$