Question

What is the nature of roots of 6/x=7-2x

Answer 1

$Given \: equation : \frac{6}{x} = 7 - 2x$

$\implies 6 = x( 7 - 2x )$

$\implies 6 = 7x - 2x^{2}$

$\implies 2x^{2} - 7x + 6 = 0$

$Compare \: above \: Quadratic \: equation \\with\: ax^{2} + bx + c = 0, we \: get$

$a = 2, b = -7 \: and \: c = 6$

$\pink{ Discreminant ( \triangle ) }\\= b^{2} - 4ac\\= (-7)^{2} - 4 \times 2 \times 6 \\= 49 - 48 \\= 1 \\\gt 0$

Therefore.,

$\green{ Roots \: are \: real\: and \: distinct}$

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Answer 2

Answer:

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