Question

what is the nature of roots of equation x2 + 10x +25 =0​

Answer 1

Answer:

Step-by-step explanation:

Taking discriminant

D=b^2-4ac

here b=10

a=1 c=25

D=100-100

D=0

So roots are real and equal which is equal to -5

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Answer 2

Answer:

In this case,

a

=

1

,

b

=

10

, and

c

=

25

. Now all we have to do is plug these values into the quadratic formula and simplify it.

x

=

−

b

±

√

b

2

−

4

a

c

2

a

x

=

−

10

±

√

10

2

−

4

(

1

)

(

25

)

2

(

1

)

x

=

−

10

±

√

100

−

100

2

x

=

−

10

±

0

2

Since adding or subtracting

0

wouldn't change the answer at all, we actually only have a single solution instead of 2 solutions.

x

=

−

10

2

=

−

5

Step-by-step explanation:

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