what is the nature of roots of equation x2 + 10x +25 =0
Answers
Answered by
5
Answer:
Step-by-step explanation:
Taking discriminant
D=b^2-4ac
here b=10
a=1 c=25
D=100-100
D=0
So roots are real and equal which is equal to -5
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Answered by
5
Answer:
In this case,
a
=
1
,
b
=
10
, and
c
=
25
. Now all we have to do is plug these values into the quadratic formula and simplify it.
x
=
−
b
±
√
b
2
−
4
a
c
2
a
x
=
−
10
±
√
10
2
−
4
(
1
)
(
25
)
2
(
1
)
x
=
−
10
±
√
100
−
100
2
x
=
−
10
±
0
2
Since adding or subtracting
0
wouldn't change the answer at all, we actually only have a single solution instead of 2 solutions.
x
=
−
10
2
=
−
5
Step-by-step explanation:
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