Question

What is the nature of roots of qadratice eqation 4x^2-12-9 =0

Answer 1

Correct Question:

What is the nature of the roots of the equation 4x²-12x-9=0?

Solution:

We have,

4x² -12x -9=0

★Comparing with ax²+bx+c=0,

a=4,b= -12 and c= -9

★Applying the Discriminant,

D=b² -4ac

=(-12)²-4(-9)(4)

=144+144

=288

=12√2

Since D>0, the roots of the equation are real and distinct.

Answer 2

Step-by-step explanation:

Hi,

4x² - 12x - 9 = 0

Here,

Coefficient of X² = 4

coefficient of x = -12

and,

Constant term = -9

Therefore,

Discriminant ( D ) = b² - 4ac

=> (-12)² - 4*4*(-9)

=> 144 + 144

=> 288 > 0

Discriminant of the given equation is greater than 0 , so it has no real roots .

Hope it will help you :)