Question

what is the nature of roots of quadratic x squre -2×+4=0?​

Answer 1

Answer:

D = -12 so, roots are  imaginary & not equal

Step-by-step explanation:

question:

x² - 4x + 4 = 0

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solution:

so, here in the equation,

x² - 2x + 4 = 0

where, a = 1 , b = -2 , c = 4

D = b² - 4ac

D = (-2)² - 4(1)(4)

D = 4 - 16

D = 12

here, D = -12 so, following the condition roots are  imaginary & not equal

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more to know:

when we have to find nature of roots

we know if the value if discriminant (D) = 0 (so , roots are real and equal)

if (D) <0(so, roots are imaginary & not equal)

if ( D ) > 0 (so, roots are real but not equal)

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hope it helps...............................

Answer 2

Answer:

not real roots

Step-by-step explanation:

write the equation first, x2-2x+4=0

find the values of a,b,c by comparing the equation with ax2+bx+c

thus, a=1,b=-2,c=4

now find the determinant D(=b2-4ac)

if D >0 roots are real

if D <0 roots are not real

if D =0 roots are equal

now,

D = (-2)2-4(1)(4)

   =4-16

   =-12

thus the roots are not real (complex roots)

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