What is the nature of the root of 2x²-4x-8=0
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Step-by-step explanation:
discriminant is greater than zero therefore two real roots of the equation exists.
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Answer:
nature of roots = real and distinct roots
Step-by-step explanation:
discriminant = b^ - 4ac
=( -4)^2 - 4 . 2 .-8
= 16 + 64
= 80 is greater than 0
therefore , two real and distinct roots
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