Question

what is the nature of the root of quadratic equation 9x² -30x+25=0​

Answer 1

To see the nature of the roots of a equation,

we have to calculate b^2-4ac , where ax^2+bx+c=0

now, the given equation is

9x² -30x+25=0 in the form of ax^2+bx+c=0

here, b^2-4ac

={(-30) ^2} -(4 *9*25)

=900-900=0

so, b^2-4ac=0

we know that, : b2– 4ac = 0

: b2– 4ac = 0When a, b, and c are real numbers, a ≠ 0 and the discriminant is zero, then the roots α and β of the quadratic equation ax2+ bx + c = 0 are real and equal.

so, the roots of 9² -30+25=0 are real and equal.

please give some feedback .