Question

what is the nature of the root of the quadratic equation 25X square - 49 equals to zero​

Answer 1

Answer:

The natural roots of 25x^2 - 49 are 7/5 and  -7/5

Step-by-step explanation:

Given 25x^2 - 49

          25x^2 - 49 = 0

          ( 5x)^2 - ( 7 )^2 = 0

          ( 5x - 7 )( 5x + 7 ) = 0    ( since c^2 - b^2 = ( a + b )( a - b )

           5x - 7 = 0  ;  5x + 7 = 0

            5x = 7       ;  5x = -7

                x = 7/5  ;   x = -7/5

 The real roots of 25x^2 - 49 are 7/5 and -7/5