what is the nature of the root of the quadratic equation
4m2-8m+9=0?
Answers
Answered by
1
Answer:
hence the root are not real
Step-by-step explanation:
The naturenature ofof thethe equationequation willwill bebe givengiven byby thethe discriminantdiscriminant :
Discrimant=b^{2} -4acDiscrimant=b
2
−4ac
if:if:
b^2-4ac=0b
2
−4ac=0
thenthen thethe rootsroots areare realreal andand equalequal
b^2-4ac < 0b
2
−4ac<0
thenthen thethe rootsroots areare notnot realreal andand complexcomplex
b^2-4ac > 0b
2
−4ac>0
thenthen thethe rootsroots areare realreal andand distinct.distinct.
b^2-4acb
2
−4ac
(-8)^2-4(4)(9)(−8)
2
−4(4)(9)
64-144=-8064−144=−80
HenceHence thethe rootsroots areare notnot realreal andand complexcomplex .
Answered by
18
Answer:
b^2-4ac=
8×8-4×4×9
=64-144
=-80
Hence, no real root
I think so
Similar questions