Math, asked by jyotshanaukey, 4 months ago

what is the nature of the root of the quadratic equation
4x {}^{2}   - 8x + 9 = 0
Real
Not real
Real and equal
wht is it​

Answers

Answered by jaidansari248
0

Answer:

to \: find \: nature \: of \: roots \: w e \: use \\ distriminate(d) =  \sqrt{ {b}^{2} - 4ac }  \\ where \: b = coefficient \: of \: x =  - 8 \\ a = coefficient \: of \:  {x}^{2}  = 4 \\ c = constant \: term = 9 \\ d =  \sqrt{ {8}^{2}  - 4(4)(9)}  \\  =  \sqrt{64 - 144}  \\   =  \sqrt{ - 80}  \\ distriminate \: is \: not \: a \: real \: number \:  \\ so \: their \: roots \: are \: not \: a \: real \: number

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