Math, asked by pradoshshinde05, 3 months ago

what is the nature of the root of the qudratic equation 2x^2-3x+5=0​

Answers

Answered by amansharma264
10

EXPLANATION.

Quadratic equation.

⇒ 2x² - 3x + 5 = 0.

As we know that,

⇒ D = Discriminant Or b² - 4ac.

⇒ D = (-3)² - 4(2)(5).

⇒ D = 9 - 40.

⇒ D = -31.

⇒ D < 0 Roots are imaginary.

                                                                                                                         

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answered by MagicalCandy
373

Answer⤵️

Given:

  • Given equation 2x² – 3x + 5 = 0

Formula:

  • ax²+ bx + c = 0

  • a= 2
  • b=(-3)
  • c=5

Solution:

  • Discriminant (D) = b² – 4ac

 = ( { - 31)}^{2} - 4 \times 2 \times 5 \\  = 9 - 40 \\  =  - 31 &lt; 0

Thus, the given equation has no real root.

  • hope this may help!
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