what is the nature of the roots of 9x^2 + 6x+ 4 = 0 ? please tell it fast
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d=b^2 -4ac
d= 6^2 - 4*9*4
D= 36 - 144
D = -108
Now,
D= - root 108
D= - root 2*2*3*3*3
D= -6root 3
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