What is the nature of the roots of the quadratic equation 2x²-3x-4=0?
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Answer:
discriminant, D=b^2-4ac
=(-3)^2-4×2×-4
=9+32
= 41
REAL ROOTS
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a = 2
b = -3
c = -4
Discriminent ( D ) = b^2 - 4ac
= ( -3 ) ^2 - ( 4 × 2 × -4 )
= 9 + 32 = 41.
D = 41.
As ; a,b,c are rational numbers, D > 0 and the value of D is not perfect square the nature of the roots are Irrational and distinct.
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