Question

What is the nature of the roots of the quadratic equation 2x²-3x-4=0?​

Answer 1

Answer:

discriminant, D=b^2-4ac

=(-3)^2-4×2×-4

=9+32

= 41

REAL ROOTS

Answer 2

a = 2

b = -3

c = -4

Discriminent ( D ) = b^2 - 4ac

= ( -3 ) ^2 - ( 4 × 2 × -4 )

= 9 + 32 = 41.

D = 41.

As ; a,b,c are rational numbers, D > 0 and the value of D is not perfect square the nature of the roots are Irrational and distinct.