Math, asked by cuteprincess111, 1 year ago

what is the nature of the roots of the quadratic equation 4x^-12x-9=0

Answers

Answered by sijasubbiah
3
Hey

Here is your answer,

b^2 - 4ac = 0
(-12)^2 - 4 x 4 x (-9) = 0
144 + 144 = 0
288 is not equal to 0.

Therefore , it has distinct real roots.

Hope it helps you!

cuteprincess111: thanx i was helpful
Answered by mathsdude85
0

SOLUTION :  

Given : 4x² - 12x - 9 = 0 .

On comparing the given equation with ax² + bx + c = 0  

Here, a = 4 , b = - 12  , c = - 9

D(discriminant) = b² – 4ac

D = (- 12)² - 4 × 4 × - 9

D = 144  + 144

D = 288

Since, D > 0  

Therefore, root of the given equation 4x² - 12x - 9 = 0 are real and distinct.

Hence, nature of roots of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct.

★★ NATURE OF THE ROOTS

If D = 0 roots are real and equal  

If D > 0 roots are real and distinct

If D < 0  No real roots  

HOPE THIS ANSWER WILL HELP YOU...

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