what is the nature of the roots of the quadratic equation 4x^-12x-9=0
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Answered by
3
Hey
Here is your answer,
b^2 - 4ac = 0
(-12)^2 - 4 x 4 x (-9) = 0
144 + 144 = 0
288 is not equal to 0.
Therefore , it has distinct real roots.
Hope it helps you!
Here is your answer,
b^2 - 4ac = 0
(-12)^2 - 4 x 4 x (-9) = 0
144 + 144 = 0
288 is not equal to 0.
Therefore , it has distinct real roots.
Hope it helps you!
cuteprincess111:
thanx i was helpful
Answered by
0
SOLUTION :
Given : 4x² - 12x - 9 = 0 .
On comparing the given equation with ax² + bx + c = 0
Here, a = 4 , b = - 12 , c = - 9
D(discriminant) = b² – 4ac
D = (- 12)² - 4 × 4 × - 9
D = 144 + 144
D = 288
Since, D > 0
Therefore, root of the given equation 4x² - 12x - 9 = 0 are real and distinct.
Hence, nature of roots of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct.
★★ NATURE OF THE ROOTS
If D = 0 roots are real and equal
If D > 0 roots are real and distinct
If D < 0 No real roots
HOPE THIS ANSWER WILL HELP YOU...
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