Question

what is the nature roots of the quadratic equation x2-15x+90=0​

Answer 1

Answer:

The nature of roots of the given quadratic equation is complex roots.

Step-by-step explanation:

The nature of roots is based on the value of discriminant (D).

If

• D > 0 ; the quadratic equation has real and distinct roots  

• D = 0 ; the quadratic equation has real and equal roots  

• D < 0 ; the quadratic equation has complex roots.

For a quadratic equation ax² + bx + c = 0 ;  

Discriminant is given by, D = b²- 4ac

 

Comparing given quadratic equation with ax²+ bx + c = 0, we get  

a = 1  

b = -15  

c = 90

Discriminant,  

D = (-15)² - 4(1)(90)

D = 225 - 360  

D = -135  

Therefore, the value of the discriminant is "-135"

-135 < 0, hence the roots of the given quadratic equation are not real roots.