What is the net current drawn by the parallel combination of tube light, electric bulb (or lamp) and the radio
set when connected with 220 V power supply.
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Answered by
6
ANSWER: 0.8181 Ampere
Also calculated the total resistance.
Explanation is in the attachment.
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Answered by
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Answer:9.35W
Explanation:
Resistance of 100Wbulb=200
=2/100=400ohms
Resistance of 60Wbulb=200
=2/60=666.67ohms
Resistance of 40Wbulb=200
=2/40=1000ohms
Therefore, total resistance in series =(400+666.67+1000)=2066.67ohms
Current in the circuit =200/2066.67=0.0967A
Therefore, actual power consumed by “40W”bulb=0.0967
=2 x 1000=9.35W (much lesser than any of the original)
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