Question

What is the net current drawn by the parallel combination of tube light, electric bulb (or lamp) and the radio

set when connected with 220 V power supply.​

Answer 1

ANSWER: 0.8181 Ampere

Also calculated the total resistance.

Explanation is in the attachment.

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Answer 2

Answer:9.35W

Explanation:

Resistance of 100Wbulb=200

=2/100=400ohms

Resistance of 60Wbulb=200

=2/60=666.67ohms

Resistance of 40Wbulb=200

=2/40=1000ohms

Therefore, total resistance in series =(400+666.67+1000)=2066.67ohms

Current in the circuit =200/2066.67=0.0967A

Therefore, actual power consumed by “40W”bulb=0.0967

=2 x 1000=9.35W (much lesser than any of the original)

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