What is the net force (magnitude and direction) on the electron moving in the magnetic field in figure given below, if B = 2 T, v = 4 x 104 m/s, and θ = 30o?
saka82411:
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the formula is f= Bqv sin theta
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Hii friend
The formula is
F= BQV sin theta
Here it is electron so negative charge.
F= 2×4×10⁴×(-1)×sin 30°
F= -4×10⁴N
Direction is opposite .
Magnitude= negative
Hope this helps you a little!!
The formula is
F= BQV sin theta
Here it is electron so negative charge.
F= 2×4×10⁴×(-1)×sin 30°
F= -4×10⁴N
Direction is opposite .
Magnitude= negative
Hope this helps you a little!!
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