Question

What is the net ionic equation of the reaction of FeCl2 with NaOH?

Answer 1

Answer:

The net ionic equation of the reaction of with NaOH is as follows.

The net ionic equation of the reaction of with NaOH is as follows.     

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1OH = 2

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1OH = 2Since, number of Cl atoms on reactant side equals 2 therefore, multiply NaCl by 2. Also, number of OH atoms on product side are 2 therfore, multiply NaOH by 2.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1OH = 2Since, number of Cl atoms on reactant side equals 2 therefore, multiply NaCl by 2. Also, number of OH atoms on product side are 2 therfore, multiply NaOH by 2.Hence, the equation will be as follows in te attachment.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1OH = 2Since, number of Cl atoms on reactant side equals 2 therefore, multiply NaCl by 2. Also, number of OH atoms on product side are 2 therfore, multiply NaOH by 2.Hence, the equation will be as follows in te attachment.please mark my answer as the brainliest.

The net ionic equation of the reaction of with NaOH is as follows.      To balance the equation, number of reactants should be equal to the number of products.Number of reactant molecules are as follows.Fe = 1Cl = 2Na = 1OH = 1Number of product molecules are as follows.Fe = 1Cl = 1Na = 1OH = 2Since, number of Cl atoms on reactant side equals 2 therefore, multiply NaCl by 2. Also, number of OH atoms on product side are 2 therfore, multiply NaOH by 2.Hence, the equation will be as follows in te attachment.please mark my answer as the brainliest.please follow me.

   

Answer 2

$\underline\bold{Question}$

what is the net ionic equation of the reaction of fe Cl2 with Na OH ?

$\huge\mathfrak\pink{Answer}$

We first write down the balanced equation for this reaction:

FeCl2(aq)+2NaOH(aq)→2NaCl(aq)+Fe(OH)2(s)⏐↓

This is a precipitation reaction, where two soluble salts are mixed together in solution forms to make a precipitate.

So, we can now write the ionic equation for this reaction, that is:

{Fe2+(aq)+2Cl−(aq)+2Na+(aq)+2OH−(aq)}

{ →2Na+(aq)+2Cl−(aq)+Fe(OH)2(s)⏐⏐↓}

Explanation:

Now, we need to cancel the spectator ions, which are ions that are present on both sides in the equation.

So, the equation becomes -

Fe2+(aq)+2Cl−(aq)+2Na+(aq)+2OH−(aq)

{→2Na+(aq)+2Cl−(aq)+Fe(OH)2(s)⏐⏐↓}

The final net ionic equation is now:

Fe2+(aq)+2OH−(aq)→Fe(OH)2(s)⏐|↓

$</strong><strong> </strong><strong> </strong><strong>The iron</strong><strong> </strong><strong>$

(II) hydroxide formed is easily oxidized when exposed to air and can easily become iron

$\huge\mathbb\green{(III) hydroxide}$

(Fe(OH)3).

$\large\underline\green {\sf hope it's helpful for you . }$

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