Question

What is the net torque about the point C for the forces shown in the following figure?

a. 15 N.m clockwise
b. 22 N.m counterclockwise
c. 2 N.m clockwise
d. 2 N.m counterclockwise

Answer 1

Answer:

b.=22N.m(counterclockwise)

Explanation:

T(torque) = F(force) * s(distance from pivot) * sin(theta), where theta is the angle between the force and the position vector.

here theta is 90°

torque =r×F(cross product)

Here I am taking directions from right hand rule,

torque=4×3(anticlock)+ 2×5(anticlock)

=22N.m(anticlockwise or counterclockwise)