Question

What is the ninth ionisation potential of fluorine atom ?

Answer 1

Answer:

number = 9th

symbol = F

name = Fluorine

9th = 106434.3

Answer 2

Answer:

The ninth ionisation potential of the fluorine atom is  1101.6 eV.

Explanation:

Ionisation potential is equivalent to the ionisation energy of the gas under study in electron volt. It is the energy required to remove the most loosely bound electron from an isolated gaseous atom to form an isolated gaseous ion.

The ninth ionisation potential of fluorine

F⁺⁸ → F⁹⁺ + e⁻

The expression for ionisation potential is

$I.E = \frac{13.6*Z^{2} }{n^{2} }$

For a fluorine atom, the value of Z is 9.

Substituting the values, we get

$I.E=\frac{13.6*9^{2} }{1^{2} }$

      = 1101.6 eV