Question

What is the no. Of atoms in 46g of sodium-23

Answer 1

the number of atoms present in sodium-23  = number of moles of sodium-23 * Avogadro's number.
therefore
number of moles = how much gram of element / atomic mass of element
therefore
number of moles = 2
therefore according to given formula
no of atoms in Na-23 = 2 * 6.022 * 10 raised to 23
that is only equal to 1.2044 * 10 raised to 24 atoms

Answer 2

Answer:

There are 1 moles in 23g of Sodium.

So there will be 2 moles in 46g of Sodium.

No. of atoms in 23g of Sodium = No. of moles * Avogadro Number

No. of atoms in 46g of Sodium = 2(No. of moles * Avogadro Number)

= 2( 1 * 6.022*10^{23}) = 12.044 * 10^23 Atoms