Chemistry, asked by laksshita24, 11 months ago

what is the no. of atoms present in 55g of molecular sulphur (S8)​

Answers

Answered by addalapoojanaidu
4

Answer:

10.309*10^23

Explanation:

Molar mass of Sulphur (S8) = 8 x 32 = 256 g / mol

No. of atoms(S) = no of moles *8*NA

NA=6.022*10^23

No. of moles = 55/256

=0.214

atoms= 0.214*8*6.022*10^23

= 10.309*10^23 atoms

Answered by yashasvisrivastava55
2

Answer:

molar mass of sulpher = (S8)=8x

32=256 g /mol

no of atoms s= no of moles

8NA

NA=6.022×10^23

no of moles = 35/256

atom=0.214×2×8.022×10^23

10.309×10^23 atoms

hope it will help you

yashasvi srivatava

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